Gujarati
Hindi
3-2.Motion in Plane
medium

A particle is moving with constant speed $\sqrt 2\,m/s$ on a circular path of radius $10\,cm$. Find the magnitude of average velocity when it has covered ${\left( {\frac{3}{4}} \right)^{th}}$ circular path

A$\frac{\pi }{3}\,m/s$
B$\frac{3}{{2\pi }}\,m/s$
C$\frac{3}{{\pi }}\,m/s$
D$\frac{4}{{3\pi }}\,m/s$

Solution

$|<\overline{\mathrm{V}}>|= \frac{\mathrm{R} \sqrt{2}}{\left(\frac{3 \pi \mathrm{R} / 2}{\mathrm{V}}\right)}=\frac{2 \sqrt{2} \mathrm{v}}{3 \pi}$
$=\frac{4}{3 \pi} \mathrm{m} / \mathrm{s}$
Standard 11
Physics

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